nox_fjmoony
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« Reply #15 on: June 21, 2009, 11:46:20 AM » |
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hey thanks Astar.
But you see its where the e part that I don't understand. I'm just starting add maths for the october november session and well I really don't understand how to get the e thingy.
And thanks a lot again.
^_^
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astarmathsandphysics
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« Reply #16 on: June 21, 2009, 12:05:29 PM » |
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I edited my post to make it clearer.
To solve the equation y=lognx raise the base to the power of both side so ny=x
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astarmathsandphysics
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« Reply #17 on: June 21, 2009, 12:10:40 PM » |
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ln x is special notation for lognx=lnx
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nox_fjmoony
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« Reply #18 on: June 21, 2009, 02:06:00 PM » |
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thanks but I have a problem in another part The part where it becomes x=e^1/2 all of a sudden. I'm quite outta practice and so don't quite understand it. Didn't understand that part in the mark scheme either. Also whats the relationship between ln and e please? Thankyou very very much Astar. ^_^ Really grateful.  |
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nox_fjmoony
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« Reply #20 on: June 21, 2009, 03:52:02 PM » |
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Ok
Another question
I guess by this time you might've guessed I"m absolutely stupid and a dunce. But I have to know this.
ok so how does lnx=1/2 becomes e^lnx=e^1/2 ?
I don't know this.
what do you do to make it like this?
I'm sorry but as you see I don't know much about ln and log and e and stuff.
Ok thanks again.
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astarmathsandphysics
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« Reply #21 on: June 21, 2009, 04:53:21 PM » |
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To eliminate a log you raise the base to the power of both sides. Here the base is e=2.718.........
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nox_fjmoony
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« Reply #22 on: June 22, 2009, 03:10:25 PM » |
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Ah Finally I get it. Thanks so much, wouldn't have known this without you tellin me. Thanks again.  |
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nox_fjmoony
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« Reply #23 on: June 23, 2009, 12:51:54 PM » |
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hey astar
Another question. Um how does e^lnx=e^1/2 become x=e^1/2 later on?
ok
thanks
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astarmathsandphysics
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« Reply #24 on: June 23, 2009, 12:54:25 PM » |
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hey astar
Another question. Um how does e^lnx=e^1/2 become x=e^1/2 later on?
ok
thanks
e^ cancels log e=ln ln is special notation for log e |
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« Last Edit: June 23, 2009, 12:58:30 PM by astarmathsandphysics »
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~Ahana~
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« Reply #25 on: September 26, 2009, 05:30:50 PM » |
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Sir, do you notes on your site for complex numbers??
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Ari Ben Canaan
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« Reply #26 on: October 20, 2009, 01:35:47 PM » |
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Scientia Est Potentia
Knowledge Itself is Power
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toobeerajpanchoo
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« Reply #27 on: October 24, 2009, 10:57:10 AM » |
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hi help in maths of cie could u please provide me formula of how to calculate interior or exterior angle of a regular polygon and also how to calculate on kinematics PLEASE SOME OTHER ALSO FORMULAS USED IN MATHEMATICS THANKS  |
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Ghost Of Highbury~
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« Reply #28 on: October 24, 2009, 11:09:07 AM » |
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hi help in maths of cie could u please provide me formula of how to calculate interior or exterior angle of a regular polygon and also how to calculate on kinematics PLEASE SOME OTHER ALSO FORMULAS USED IN MATHEMATICS THANKS if n=number of sides interior angle = ((n-2)*180)/n which kinematics formula u want exactly? v=u + at s = ut + 0.5at 2v 2 = u 2 + 2as s = (u+v)t/2 |
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divine intervention!
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wassup
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« Reply #29 on: October 24, 2009, 11:09:47 AM » |
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hi help in maths of cie could u please provide me formula of how to calculate interior or exterior angle of a regular polygon and also how to calculate on kinematics PLEASE SOME OTHER ALSO FORMULAS USED IN MATHEMATICS THANKS n=No. of sides Sum of interior angles=180(n-2) One interior angle=Sum of interior angles/n One exterior angle=180 o-One interior angle |
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